Question

a mans age is 3 times that of his sons age after 12 years the fathers age will be double the sons age what is the age of each

Answer 1

Let the age of son be a

Father's age = 3a


After 12 years,

Son's age = a+12

Father's age = 3a +12


=> 2( a+12) = 3a +12

=> 2a + 24 = 3a +12

=> 3a - 2a = 24-12

=> a = 12


Son's age = 12 years

Father's age = 36 years

Answer 2

Let the man's age be x
and the son's be y

x = 3y .....( i )

After 12 years

Man's age :- x + 12
Son's age :- y + 12


x + 12 = 2 ( y + 12 )

x + 12 = 2y + 24

x - 2y = 24 - 12

x - 2y = 12 ..... ( ii )

Putting the value of x from i in ii

x - 2y = 12

3y - 2y = 12

y = 12

Putting in ( i )

x = 3y

x = 3 × 12

x = 36


Man's age is 36years
Son's age is 12 years