Question

A manufacturer of laptop produced 6000 units in 3rd year and 7000 units in 7th year such that production increases uniformly by a fixed number every year. (i) Production in first year (ii) Units of Production in fifth year (iii) Total units of production in 7 years​

Answer 1

Answer:

Since, production of Laptops in 3rd year = 6000

=> a3 = 6000 => a + 2d = 6000 ....(i)

Also production of laptops in 7th year = 7000

a7 = 7000 => a + 6d = 7000 ...(ii)

Subtracting (i) from (ii), we get

4d = 1000 => d = 250

From (i), a + 2 (250)= 6000 => a = 5500

Hence, production in fifth year

a5 = a + 4d =(5500 +4(250)) = 6500 units

Answer 2

Answer:

Step-by-step explanation:

Since, production of Laptops in 3rd year = 6000 => a3 = 6000 => a + 2d = 6000        ....(i) Also production of laptops in 7th year = 7000 a7 = 7000 => a + 6d = 7000     ...(ii)      Subtracting (i) from (ii), we get 4d = 1000 => d = 250 From (i), a + 2 (250)= 6000 => a = 5500 Hence, production in fifth year a5 = a + 4d =(5500 +4(250)) = 6500 unitsRead more on Sarthaks.com - https://www.sarthaks.com/250520/a-manufacturer-of-laptop-produced-6000-units-in-3rd-year-and-7000-units-in-the-7th-year