A marble rolling on a smooth floor has an initial velocity of 0.4m/s.If the floor offers a retardation of 0.2 m/s². calculate the time it will take to come at rest
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u=o.4m/s
v=0(came to rest)
t=?
acceleration=0.2m/s^2
a=v-u/t
0.2=0-0.4/t
0.2=-0.4/t
0.2t=0.4
t=0.4/0.2=2 sec
hope it helps!!
v=0(came to rest)
t=?
acceleration=0.2m/s^2
a=v-u/t
0.2=0-0.4/t
0.2=-0.4/t
0.2t=0.4
t=0.4/0.2=2 sec
hope it helps!!
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