Question

A marble rolling on smooth floor has an initial velocity of 0.4 m/s. If the floor offers a
retardation of 0.02 m/s 2 , Calculate the time it will take to come to rest.

Answer 1

Answer:

we know that

v = u + at

the time taken will be given as

t = (v - u) / a

given

u = 0.4 m/s

v = 0 (comes to rest)

a = -0.02 m/s2 (retardation)

so,

t = (0 - 0.4) / 0.02

thus,

t = 20s