Question

a marble tile is of length 12 cm and width 10 cm .how many tiles are needed to cover a rectangular region 440 cm long and 300 cm wide​

Answer 1

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \boxed{\boxed { \huge \mathcal\red{ solution}}}}$

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$\huge \star$For the Rectangular Region:

Length(l)=440 cm

breadth (b)=300 cm

$\therefore$Area=(l×b) cm²

$\rightarrow$Area=(440×300) cm²

$\huge \star$For the tile:

Length(l)=12 cm

breadth (b)=10 cm

$\therefore$Area of each tile=(l×b) cm²

$\rightarrow$Area of each tile=(12×10) cm²

$\huge \star$Number of Tiles:

$\implies \frac{area \:of\: rectangular \:region}{area \:of \:each \:tile}\\</p><p>\implies \frac{\cancel{44}\cancel0\times 300}{\cancel{12}\times1\cancel0}\\</p><p>\implies \frac{11\times\cancel{3}00}{\cancel3}\\ \implies \boxed{\red{ 1100\: pcs }}$

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$\underline{ \huge\mathfrak{hope \: this \: helps \: you}}$

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Answer 2

$\huge\mathbb{SOLUTION:-}$

• We have to find how many tiles needed for floor dimensions 440×300

$\bf\underline{\underline{According\: To\: Question:-}}$

• First find the Area of tiles which is in the form of rectangle

$\bold{Given:-}\begin{cases}\sf{Tiles \:Length(l)=12cm}\\ \sf{width\:of\:Tile=10cm}\end{cases}$

$\boxed{\sf{Area\:of\: rectangle=length\times breadth}}$

$\sf\implies Area_{tiles}=12\times 10\\ \\ \sf\implies Area_{tiles}=120cm{}^{2}$

• Now find the Area of floor

$\bold{Given:-}\begin{cases}\sf{Length(l)=440cm}\\ \sf{width=300cm}\end{cases}$

$\sf\implies Area_{rectangular\: region}=440\times 300\\ \\ \sf\implies Area_{rectangular\: region}=13200cm{}^{2}$

$\boxed{\sf{\red{Area\:of\:tiles=120cm{}^{2}}}}$

$\boxed{\sf{\red{Area\:of\: rectangular\: region=132000cm{}^{2}}}}$

• Now we have to find how many tiles will be required for floor

$\boxed{\sf{No.\:of\:tiles= \frac{Area\:of\: rectangular\: region}{Area\:of\:tiles}}}$

$\sf\implies Tiles=\cancel{\frac{132000}{120}}\\ \\ \sf\implies Tiles=1100$

$\boxed{\sf{\purple{Tiles\:needed=1100}}}$

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