Math, asked by maheshindia1952, 1 year ago

A marble tile measures 10 cm x 8 cm. How many tiles will be required to cover a wal
size 6 m * 4 m? Also find the total cost of the tiles at 25 per tile.​

Answers

Answered by samyaksonawane03
2

Answer:

It will cost rs.750

Step-by-step explanation:

Given.length of tile=10cm

breadth of tile=8cm

wall length=6m

wall breadth =4m

First calculate the area of the tile.

The tile is a rectangle.

hence,Area of rectangle=length×breadth.

= 10×8

=80 sq.cm

Area of wall=length ×breadth

=6×4

=24m

Convert m into cm

24 ×100cm

=2400cm

Therefore,2400÷80

=30

No.of tiles=30

Cost of 1 tile=rs.25

25×30

=750

Ans.The cost for 30 tiles will rs.750

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Answered by Anonymous
0

Step-by-step explanation:

One tile=12×10=120cm,wall=4×3 =12m,1m=100cmso,12m=1200cm.to find no.of tiles =1200÷120=10.co

wwwumashankar1madhu

Total cost=22.50×10=225/-

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