Question

A mass 5kg is suspended by a string 10m long .A horizontal force is applied on the mass to pull it 5m from vertical line through the point of suspension.find magnitude of force

Answer 1

There are three forces weight 5g, F and T acting on the mass at B.

Applying triangle law of vectors

(F/ AB)= (5g/OA)

F=5g x (AB/OA)

= (5x9.8) x (5/10)

=24.5 N

Answer 2

Answer:

There are three forces weight 5g, F and T acting on the mass at B.

Class_11_Motion_In_A_Plane_Figure2

Applying triangle law of vectors

(F/ AB)= (5g/OA)

F=5g x (AB/OA)

= (5x9.8) x (5/10)

=24.5 N