Question

A mass is moving at 2m/s.What velocity qill double its K.E?​

Answer 1

Answer:

Solution

as we know that

${v}^{2} \: \alpha \: \: ke - - - - - - - (1)$

where

$\alpha = directly \: praporsanate \:$

ie as V² increase K also increase

then V = 2m/s (given)

so

but we want double

so now

${ \sqrt{v} }^{2} \alpha \: ke$

then

$\sqrt{ {2}^{2} } \alpha \: \: ke \:$

$\sqrt{4} \: \: \alpha \: ke$

$2 \: \alpha \: ke \:$

hence proved

so velocity must be 1.414

coz

$\sqrt{v} = \sqrt{2} = 1.414m {s}^{ - 1}$

hope it helps

be brainly