Question

a mass m=20g has a charge q=3C it moves with velocity 20m/s and enters a region of electric field of 80N/C in the same direction of velocity .the velocity of mass after 3 sec is​

Answer 1

V = u + at = 20 + 3(80)3/0.2 = 3620 m/s

Answer 2

The velocity of mass after 3 sec is​ 36020 m/s.

Explanation:

Given the mass of the charge, m 20 g.

The charge on the mass, q =3 C.

The initial velocity of the charge, u = 20 m/s.

The electric field, E = 80 N/C.

First we have to calculate the acceleration of the charge, use the relation between force, electric field and charge as,

F = q E

OR,

ma = qE

$a=\frac{qE}{m}$

substitute the values, we get

$a=\frac{3C\times80N/C}{0.02kg}$

$a=12000m/s^2$

Now to calculate the velocity after 3 s, use first equation of motion.

v = u + at

substitute the values, we get

v = 20 m/s + 12000m/s^2 x 3 s

v = 36020 m/s.

Thus, the velocity of mass after 3 sec is​ 36020 m/s.

#Learn More: equation of motion, electric field.

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