a mass m=20g has a charge q=3C it moves with velocity 20m/s and enters a region of electric field of 80N/C in the same direction of velocity .the velocity of mass after 3 sec is
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V = u + at = 20 + 3(80)3/0.2 = 3620 m/s
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The velocity of mass after 3 sec is 36020 m/s.
Explanation:
Given the mass of the charge, m 20 g.
The charge on the mass, q =3 C.
The initial velocity of the charge, u = 20 m/s.
The electric field, E = 80 N/C.
First we have to calculate the acceleration of the charge, use the relation between force, electric field and charge as,
F = q E
OR,
ma = qE
substitute the values, we get
Now to calculate the velocity after 3 s, use first equation of motion.
v = u + at
substitute the values, we get
v = 20 m/s + 12000m/s^2 x 3 s
v = 36020 m/s.
Thus, the velocity of mass after 3 sec is 36020 m/s.
#Learn More: equation of motion, electric field.
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