Question

A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes simple harmonic oscillations with a time period T. If the mass is increased by m, then the time period

becomes(5/4T). The ratio of is m/M

(A) 9/16 (B) 5/4 (C) 25/16 (D) 4/ 5​

Answer 1

Answer:

From formula 1, we can say

T=2π

k

M

...(1)

Also,

3

5T

=2π

k

M+m

...(2)

Dividing eqn 2 and 1, we get

3

5

=

M

M+m

∴

9

25

=

M

M+m

∴

9

25

=1+

M

m

Hence, answer=16/9, i.e. option B

Answer 2

Answer:

$options \: \: (b)$