A mass m1 of 100 kg travelling with a uniform velocity of 5 m/s along a line collides with a stationary mass m2 of 1000 kg. after the collision, both the masses travel together with the same velocity. the coefficient of restitution is
Answers
Answered by
1
Coefficient of restitution = ( velocity of separation )/(velocity of approach)
e.g., Coefficient of restitution = (v₂ - v₁)/(u₁ - u₂)
v₂ is the final velocity of 2nd body after impact
v₁ is the final velocity of 1st body after impact
u₁ is the initial velocity of 1st body before impact
u₂ is the intial velocity of 2nd body before impact .
Now, given,
u₁ = 5m/s , u₂ = 0 , v₁ = v₂ = v [ ∵ after collision velocity of both are same velocity]
Now, Coefficient of restitution = (v - v)/(5 - 0) = 0
Hence , answer is 0
e.g., Coefficient of restitution = (v₂ - v₁)/(u₁ - u₂)
v₂ is the final velocity of 2nd body after impact
v₁ is the final velocity of 1st body after impact
u₁ is the initial velocity of 1st body before impact
u₂ is the intial velocity of 2nd body before impact .
Now, given,
u₁ = 5m/s , u₂ = 0 , v₁ = v₂ = v [ ∵ after collision velocity of both are same velocity]
Now, Coefficient of restitution = (v - v)/(5 - 0) = 0
Hence , answer is 0
Similar questions