a mass of 0.1 kg is rotated in a vertical circle using a string of length one metre. when the string makes an angle 30 degree with the vertical, the speed of the mass is 2 metre second inverse one.the radial acceleration of the mass at that instant is
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Dear Student,
● Answer -
a = 12.49 m/s^2
● Explaination -
# Given -
m = 0.1 kg
v = 2 m/s
r = 1 m
θ = 30°
# Solution -
Radial acceleration of the mass at any instant in vertical circular motion -
a = v²/r + gcosθ
Substitute values,
a = 2²/1 + 9.8cos30°
a = 4/1 + 9.8×0.866
a = 4 + 8.487
a = 12.49 m/s^2
Therefore, radial acceleration of the mass at that instant is 12.49 m/s^2.
Thanks dear.
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