Question

a mass of 10 gram moving with a velocity of 2m per second strikes a pendulum Bob of mass 10g the two masses strike together the maximum height reached by the system now

Answer 1

I think it will help you

Answer 2

Answer:

h = 0.81 m

Explanation:

Given,

• Mass of the object = m = 10 g
• Mass of the bob = M = 10 g
• Initial speed of the object = v = 2 m/s.

Hence From the conservation of mechanical energy of the system of masses,

Initially, the objects contain some kinetic energy but the bob's kinetic energy is zero due to at rest. And potential energies of both the particles is zero due to assuming the base height at that instant place.  

Finally, at the maximum height, both kinetic energies are zero but due to attaining some height bob got some potential energy.

Let h be the maximum height attained by the pendulum bob,

$\therefore K.E_i\ +\ P.E_i\ =\ K.E_f\ +\ P.E_f\\\Rightarrow \dfrac{1}{2}mv^2\ +\ 0\ =\ 0\ +\ Mgh\\\Rightarrow h\ =\ \dfrac{mv^2}{2Mg}\\\Rightarrow h\ =\ \dfrac{10\times 4^2}{2\times 10\times 9.81}\\\Rightarrow h\ =\ 0.81\ m$

Hence the maximum height attained by the bob is 0.81 m.