A mass of 1kg is attached to the middle
of a rope, which is being pulled from both end in the opposite direction taking g=10m/sec the minimum pull required to completely straighten the rope will be
Answers
Answered by
2
Answer:
mass=1kg
g=10m/sec
f=m×g
f=1×10
f=10N
Answered by
4
Answer:
mass=1kg
g=10m/sec
f=m×g
f=1×10
f=10N
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