Science, asked by sub61, 11 months ago

A mass of 1kg is attached to the middle
of a rope, which is being pulled from both end in the opposite direction taking g=10m/sec the minimum pull required to completely straighten the rope will be

Answers

Answered by chatterjeeshraboni19
2

Answer:

mass=1kg

g=10m/sec

f=m×g

f=1×10

f=10N

Answered by diptisarkar539
4

Answer:

mass=1kg

g=10m/sec

f=m×g

f=1×10

f=10N

Hope it helps you

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