Question

A mass of 2 kg attached to a spring of force constant 260 N m⁻¹ makes 100 oscillations. What is the time taken?

Answer 1

Hey mate,

● Answer- 55.25 s

● Explaination-
# Given-
m = 2 kg
k = 260 N/m
f' = 100 oscillations

# Solution-
Angular velocity is
ω = √(k/m)
ω = √(260/2)
ω = √130
ω = 11.4 rad/s

Frequency of oscillations-
f = ω/2π
f = 11.4/(2×3.14)
f = 1.82 Hz

Time taken is given by-
t = f'/f
t = 100/1.82
t = 55.25 s

Time taken for 100 oscillations is 55.25 s.

Hope that is useful...