Question

A mass of 200 g is attached to a cord wound over a Flywheel of circumference 60cm and axle diameter 2.65 cm. When the mass is released from rest, the wheel makes 10revolutions in 20 s. Calculate the mass of the flywheel.​

Answer 1

cord is wound over the rim of a flywheel of mass, M = 20 kg and radius, R = 25cm = 0.25m.

A mass,m = 2.5 kg is attached to the cord is allowed to fall under gravity.

here, torque = weight × perpendicular distance on weight from axis of rotation to circumference of rim as shown in figure.

or,

here, I is moment of inertia of rim of flywheel, I = 1/2MR²

so, 1/2 MR² = mgR

or, MR = 2mg

or, = 2mg/MR

= 2 × 2.5 × 10/20 × 0.25

= 10 rad/s²

hence, angular acceleration is 10 rad/s²

I hope that it would help you and Mark me as the brainliest and please follow me and have a nice dream

Answer 2

Answer:

a²-b²+2bc-c² =a² - (b² -2bc +c²)

=a² - (b-c)²

=(a-(b-c))(a+(b-c))

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ [ using identity a²-b² =(a-b)(a+b) ]

= (a-b+c)(a+b-c)

hence.,a²-b²+2bc - c² = (a-b+c)(a+b-c)