Question

A mass of 5 kg is at a point A on a table. It is moved to a point B, 25 cm away by applying a force of 20 N in the direction of force . What is the work done on the object by-
(i) the gravitational force and
(ii) the applied force ​

Answer 1

Answer:

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Answer 2

${\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}}$

$\:\:\:\:\bullet\:\:\:\sf{Mass \: of \: object(m) = 5 \: kg }$

$\:\:\:\:\bullet\:\:\:\sf{Force(F) = 20 \: N}$

$\:\:\:\:\bullet\:\:\:\sf{Displacement(s) = 25 \: cm}$

${\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}}$

$\:\:\:\:\bullet\:\:\:\sf{Work \: done \: by \: gravity \:( W.D_{g}) }$

$\:\:\:\:\bullet\:\:\:\sf{Work \: done \: by \: force\:( W.D_{F})}$

${\mathfrak{\underline{\purple{\:\:\: Calculation:-\:\:\:}}}}$

☯ According to the given data

$\\ \:\:\:\:\bullet\:\:\:\sf{s = \dfrac{25}{100} = 0.25\:m}$

$\:\:\:\:\bullet\:\:\:\sf{cos \: \theta_{1} = 90 \degree}$

$\:\:\:\:\bullet\:\:\:\sf{cos \: \theta_{2} = 0 \degree}$

☯ Finding the work done by gravity

$\dashrightarrow\:\: \sf{ W.D_{g} = mg \: s \: cos \: \theta_{1}}$

$\dashrightarrow\:\: \sf{W.D_{g} =5 \times 10 \times 0.25\times cos \: 90 \degree }$

$\dashrightarrow\:\: \sf{ W.D_{g} =12.5 \times 0 }$

$\dashrightarrow\:\: {\boxed{\sf{W.D_{g} =0 \: joule }}}$

☯ Finding the work done by force

$\dashrightarrow\:\: \sf{ W.D_{F} = F\: s \: cos \: \theta_{2}}$

$\dashrightarrow\:\: \sf{W.D_{F} =20 \times 0.25 \times cos \: 0 \degree }$

$\dashrightarrow\:\:{\boxed{\sf{W.D_{F} = 5 \: joule }}}$