A mass of 50 kg was moving with a velocity 400 m/s. A force of 40000 N is applied on the mass and its velocity is reduced to 50 m/s after some time. What is the distance travelled by the mass during this period?
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Mass = 50 kg
u = 400 m/s
v= 50 m/s
F = 40000 N
t = unknown
Distance travelled in time t =?
Acceleration = a = F/m = 40000/50 = 800 m/s²
Again, acceleration a = change of velocity /t
or, t = change of velocity/a = 350/800 sec
★ Distance travelled: s = ut – (1/2)a t²
= 400 * (350/800) – (1/2) 800. (350/800)²
= 175 – 76.5 = 98.5 m
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