Question

A mass of 50kg is on a rough horizontal floor. The coefficient of static friction between the surfaces is 0.4. Find the limiting frictional force acting on the block. (g=10m/s.)​

Answer 1

Explanation:

N=50g−Fcos30∘

FSin30∘=f=μN

2

F

=(500−

2

F√3

)μ

F=(1000−F√3)0.6

2.03F=600

F=294.3N

solution

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