Question

A mass of 50kg is on a rough horizontal floor .The coefficient of static friction between the surfaces is 0.4. Find the limiting frictional force acting on the block. ( g=10m/s²)​

Answer 1

Answer:

f = μN

N =mg

so mg = mass x g = 50 x 10 = 500 N

SO N = 500 N

f = μN

f = 0.4 x 500 N

f = 200 N

SO THE LIMITING FRICTION ACTING ON THE BLOCK IS 200 N

Explanation:

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Answer 2

Answer:

f = μN

N =mg

so mg = mass x g = 50 x 10 = 500 N

SO N = 500 N

f = μN

f = 0.4 x 500 N

f = 200 N

SO THE LIMITING FRICTION ACTING ON THE BLOCK IS 200 N

Explanation:

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Explanation: