Physics, asked by ish911, 11 months ago

A mass rotates in a vertical circle of radius R and has a circular speed at the top. lf the radius of the circle is increased by a factor of 4, circular speed at the top will be
A) decreased by a factor of 2
B) decreased by a factor of 4
C) increased by a factor of 2
D) increased by a factor of 4

Answers

Answered by harshith4123
3

Answer:

c]increased by a factor of 2

Explanation:

speed of the particle at the top of the vertical circle iS

v=\sqrt{g*R}

given that the radius of the circle is increased by a factor of 4

then v'=\sqrt{g*4R}

          =2\sqrt{g*R}

          v'=2v

therefore,it is increased by a factor of 2

Answered by Adityaganjoo03
0

Answer:

C) increased by a factor of 2

Explanation:

Since at the top of the circulation motion weight equals to the centripetal force i.e., v=\sqrt{gR}

⇒v= \sqrt{g *4R\\}

​     =2\sqrt{gR}  

Therefore if we increase the radius by a factor 4, the circular speed at the top will be increased by a factor of 2.

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