Question

A mass tied to a string moves in a vertical circle
with a uniform speed of 5 m/s as shown. At the
point P the string breaks. The mass will reach a
height above P of nearly :-​

Answer 1

Answer:

Explanation:the answer is given the photo below

Answer 2

Answer:

The height is 1.27 m.

Explanation:

Given that,

Speed = 5 m/s

Suppose the radius of the circle is 1 m.

We need to calculate the acceleration

Using formula of acceleration

$a =\dfrac{v^2}{r}$

Where, v = speed

r = radius

Put the value into the formula

$a=\dfrac{5^2}{1}$

$a =25\ m/s^2$

We need to calculate the height

Using equation of motion

$v^2=u^2+2gh$

Put the value in the equation

$25=0+2\times9.8\times h$

$h=\dfrac{25}{2\times9.8}$

$h=1.27\m$

Hence, The height is 1.27 m.