Question

A mass weighing 4 pounds is attached to spring whose spring constant is 16lb/ft.What is period of simple harmonic motion.​

Answer 1

Answer:

Explanation:

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Answer 2

Given: A mass weighing 4 pounds is attached to spring whose spring constant is 16lb/ft.

To find: Period of simple harmonic motion

Explanation: Mass(m) = 4 pounds

Spring constant (k)= 16lb/ft

lb and pounds are the same units of mass and denote the same measurement of mass.

Time period of Simple harmonic motion is given by:

$t = 2\pi \sqrt{ \frac{m}{k} }$

$t = 2 \times 3.14 \times \sqrt{ \frac{4}{16} }$

$t = 6.28 \sqrt{ \frac{1}{4} }$

$t = \frac{6.28}{2}$

t= 3.14 seconds

Therefore, the time period of this simple harmonic motion is 3.14 seconds.