Question

A match box measures 4 cm x 2.5 cm x 1.5 cm. How many such packets can be placed in a card box having measuring 40 cm x 30 cm x 24 cm?​

Answer 1

ANSWER:

= 43200cm^3. = 480 packets.

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Answer 2

❍ Given :-

Measure of matchbox :-

• Length = 4 cm
• Breadth = 2.5 cm
• Height = 1.5 cm

We know that,

$\sf \fbox{→Volume = l \times b \times h}$

$\sf → Volume = 4 × 2.5 × 1.5$

$\sf → \fbox \red{Volume = 15 {cm}^{3}}$

Now, Volume of 1 matchbox = 15cm³

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❍ Given :-

Measures of cardboard box :-

• Length = 40 cm
• Breadth = 30 cm
• Height =24 cm

$\sf \fbox{→Volume = l \times b \times h}$

$\tt →Volume = 40 \times 30 \times 24$

$\tt →\fbox \red{Volume = 28800 {cm}^{3}}$

Therefore the number of such packets can be placed a cardboard box are,

$\tt = \dfrac{Volume \: of \: cardboard \: box}{Volume \: of \: one \: matchbox}$

$\tt = \dfrac{28800}{15} {cm}^{3}$

$\tt = \fbox \green{1920 \: packets}$

Hence, 1920 packets can be placed in the cardboard box.