Question

A match box measures 5 cm x 4 cm x 3 cm. what will be the volume of a packet
containing 12 such match boxes?​

Answer 1

Answer:

${\mathtt{\large{\underline{given }}}}$

• Length = 5cm
• Breath = 4cm
• Height = 3 cm

${\mathtt{\large{\underline{To \: find }}}}$

Volume

${\mathtt{\large{\underline{solution}}}}$

✯ Here the dimension of matchbox is given.

we know that the shape of matchbox is cuboid so we have to calculate the volume of a cuboid.

volume of the cuboid is given as :-

${\underline{\boxed{\sf{volume = length×breath×height}}}}$

$\sf{\implies Volume \: of \: matchbox = 5×4×3} \\ \\\sf{\implies Volume \: of \: matchbox = 60cm³}$

• so the volume of single box is 60cm³

→$\sf{Volume\: of \:12\: boxes= 12 ×60 cm³}$

(By unitary Method )

→Volume of 12 boxes = 720 cm³

• The required answer is 720cm³

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More to know !!

✏️LSA (cuboid) = 2h(l + b)

✏️TSA(cube) = = 6a²

✏️TSA (cuboid)= 2(lb + bh +lh)

✏️LSA of cube = 4a²

✏️TSA of cylinder = 2πr (h + r)

✏️CSA of Cylinder= 2π × r × h

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Answer 2

Answer:

Given

• Lenght = 5 cm

• Breadth = 4 cm

• Height = 3 cm

To Find

• Volume of 12 matchbox

Using Concept

• Here I am using formula of volume of cuboid.

Using Formula

• Volume of cuboid = (Length × Breadth × Height)

Full Solution

❶ Firsty we will find the volume of a matchbox.

So,

${ : \red\implies\sf \pink{Volume }_{(cuboid)}= \purple{( 5 \: cm) \times (4 \: cm)\times( 3 \: cm)}}$

${: \red\implies \sf \pink{Volume}_{(cuboid)} = \purple {(5 \times 4 \times 3) (cm \times cm \times cm)}}$

$: \red \implies \sf\pink{Volume}_{(cuboid)} = \purple{ 60 \: {cm}^{3} }$

The Volume of 1 matchbox is 60 cm³

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❷ Now we find the volume of 12 matchbox.

So,

$: \red\implies\sf \purple{Volume} = \pink{ (60 \: {cm}^{3} ) \times 12}$

$: \red\implies \sf \purple{Volume}= \pink{ (60 \times 12) \: {cm}^{3} }$

$: \red\implies \sf \purple{Volume} = \pink {720 \: {cm}^{3}}$

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Therefore

The volume 12 matchbox is 720 cm³.