Question

A matchbox measures 4 cm x 2.5 cm x 1.5 cm. What will be the volume of a packet
containing 12 such boxes?​

Answer 1

Given:

• Dimension of matchbox = 4 cm × 2.5 cm × 1.5 cm

⠀⠀⠀

Need to find:

• Volume of a packet containing 12 such boxes?

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

$\frak{Here} \begin{cases} & \sf{Length, l = \bf{4\;cm}} \\ & \sf{Breadth, b = \bf {2.5\;cm}} \\ & \sf{Height, h = \bf{1.5\;cm}} \end{cases}$

⠀⠀⠀

We know that,

⠀⠀⠀

Matchbox is in cuboidal shape.

⠀⠀⠀

Therefore,

⠀⠀⠀

$\star\;{\boxed{\sf{\purple{Volume_{\;(cuboid)} = l \times b \times h}}}}$

$\qquad:\implies\sf 4 \times 2.5 \times 1.5$

$\quad\;\;\;:\implies{\boxed{\frak{\pink{15\;cm^3}}}}\;\bigstar$

$\therefore\;{\underline{\sf{Volume\;of\;one\;matchbox\;is\; \bf{15\;cm^3}.}}}$

⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

☯ Now, Finding Volume of packet containing 12 such boxes,

⠀⠀⠀

$:\implies\sf 12 \times Volume\;of\;one\;matchbox$

$\qquad\qquad:\implies\sf 12 \times 15$

$\qquad\quad:\implies{\boxed{\frak{\purple{180\;cm^3}}}}\;\bigstar$

$\therefore\;{\underline{\sf{Hence,\;Volume\;of\;packet\;containing\;12\;such\;boxes\;is\; \bf{180\;cm^3}.}}}$

Answer 2

Explanation:

Vol. of cuboid=l*b*h

Vol. of 1 matchbox=4*2.5*1.5

=15cm3

Vol. of 12 matchboxes=15*12

180 cm3