Question

A material of length L, and area of cross section A has resistivity equal to ⍴. It is cut into
three equal parts by length. What will be the resistivity of each segment now?

Answer 1

Answer:

new resistivity = resistivity/9

Explanation:

resistivity = resistance × A/ L

Answer 2

Answer:

(i) Resistivity will not change as it depends on the nature of the material of the conductor. (ii) The length of each part becomes L/4. ρ,A constant. R=ρL/A. Resistance of each part = Rpart= (ρL/4)/A = R/4. (a) In parallel the 1/Reqv = 1/Reqv +1/Reqv +1/Reqv +1/Reqv = 4/Reqv = 16R →Reqv = R/16 Ω (b) In series the Reqv= R/4+ R/4 +R/4+R/4=R Ω (iii) P=V2 /R. If Reqv is less, power consumed will be more. In the given case, Reqv is lesser in the parallel and power consumed will be more.Read more on Sarthaks.com - https://www.sarthaks.com/503836/consider-conductor-of-resistance-length-thickness-and-resistivity-now-this-conductor-is