A maximum 50mA current can be allowed to flow through a 19.81 coil of galvanometer. The galvanometer 209 is used to be measure 5A maximum current. Calculate the length of a copper wire to be used as a shunt. The diameter of the wire is 4mm (for copper p=1.6x10-4.m).
Answers
Answered by
1
Answer:
Correct option is
C
3
The shunt resistance used is given by:
S =
I−I
g
I
g
G
=
5−0.05
0.05×50
=
4.95
2.5
=
495
250
=
99
50
Ω
We know that,
∵ S=
A
ρl
or l=
ρ
SA
l=
99
50
×
5×10
−7
3×10
−6
=3.0m
Answered by
2
Answer:
50 m Current can be -
19.81 + 209 - 5A P=1.6x10-4.m P = 5A
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