Question

find the sum of all 3 digit numbers which leave remainder 5 on division by 8 pls answer
correct answer ​

Answer 1

Step-by-step explanation:

Three digit numbers = 100-999

Three digit numbers which leave remainder of 5 when divided by 8 = (Three digit numbers divisible by 8) + 5

First number = 104+5 = 109

Second number = 109+8 = 117

Third number = 117 + 8 = 125

And so on till the last digit which is 993

Then we will add all these digits and get the desired answer.

Answer 2

Answer:

The sum of all 3 digit numbers which leave 5 as remainder when divided by 8 is 62037.