A mechanic buys an old refrigerator for 2130 and spends 1624 on repairing and painting it. If the refrigerator is sold for 3735.23, find the mechanic's gain or loss per cent.
Answers
Solution!!
CP of old refrigerator = Rs 2130
Cost of repairing and painting = Rs 1624
Total CP = Rs 2130 + Rs 1624 = Rs 3754
Given that SP = Rs 3735.23
As we can observe, the CP > SP so, the mechanic suffers a loss.
Loss = CP - SP
Loss = Rs 3754 - Rs 3735.23
Loss = Rs 18.77
Loss% = (Loss/CP) × 100
Loss% = (18.77/3754) × 100
Loss% = 0.005 × 100
Loss% = 0.5
Abbreviations used:-
CP → Cost Price
SP → Selling Price
More information:-
When SP > CP, there is profit.
When CP > SP, there is loss.
Profit = SP - CP
Loss = CP - SP
Profit% = (Profit/CP) × 100
Loss% = (Loss/CP) × 100
Answer:
Answer is 0.5% loss (plz mark me brainliest)
Step-by-step explanation:
Solution!!
CP of old refrigerator = Rs 2130
Cost of repairing and painting = Rs 1624
Total CP = Rs 2130 + Rs 1624 = Rs 3754
Given that SP = Rs 3735.23
As we can observe, the CP > SP so, the mechanic suffers a loss.
Loss = CP - SP
Loss = Rs 3754 - Rs 3735.23
Loss = Rs 18.77
Loss% = (Loss/CP) × 100
Loss% = (18.77/3754) × 100
Loss% = 0.005 × 100
Loss% = 0.5
Abbreviations used:-
CP → Cost Price
SP → Selling Price
More information:-
When SP > CP, there is profit.
When CP > SP, there is loss.
Profit = SP - CP
Loss = CP - SP
Profit% = (Profit/CP) × 100
Loss% = (Loss/CP) × 100