Question

A mechanic can open a nut by
applying a force of 120N while
using a lever handle of length
40cm. What is the length of the
handle required if he wants to
apply the force of only 30N.​

Answer 1

Answer:

torque=length of lever × force applied

so

torque required = 120×40=4800

now the new length of handle required =

30×x=4800

x=4800/30

x=160cm

Answer 2

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