Physics, asked by farhanmohammad6089, 9 months ago

A mechanic strikes a nail with a hammer moving with a velocity of 20 m/s. The hammer comes to rest in 0.02 s after striking the nail. Calculate the acceleration of the nail.

Answers

Answered by Shermx
3

Answer:

A=v/t=0-20/0.02=-1000m/s2

Explanation:

Answered by Anonymous
13

Explanation:

Given :

  • Initial Velocity ( u ) = 20 m/s

  • Final Velocity ( v ) = 0 m/s

  • Time Taken ( t ) = 0.002 s

\underline{\bigstar\:\textsf{According to the given Question :}}

:\implies\sf Acceleration=\dfrac{Final\: Velocity-Inital\: Velocity}{Time}\\\\\\:\implies\sf Acc^{n} = \dfrac{0 - 20}{0.002}\\\\\\:\implies\sf Acc^{n} = \dfrac{ - 20}{0.002}\\\\\\:\implies\sf Acc^{n} = \dfrac{ - 20 \times 1000}{2}\\\\\\:\implies\sf Acc^{n} =  - 10 \times 1000\\\\\\:\implies\underline{\boxed{\sf Acc^{n} =  - 10000\:m\:s^{-2}}}

\therefore\:\underline{\textsf{Acceleration of hammer would be \textbf{- 10000 m s$^{\text{-2}}$}}}.

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