Question

A mechanic strikes a nail with a hammer of mass 500g moving with a velocity of 20m/s. The hammer comes to rest in 0.02s after striking the nail. Calculate the force exerted by the nail on the hammer.

Answer 1

here m=500g =>1/2 kg
u=20m/s
v=0
t=0.02 seconds

V=U+AT
0=20+0.02A
-20=0.02A
A=-1000 m/s^2

F=ma
F=1/2 (-1000)
F=-500 N

Well hope this is the answer

Answer 2

Answer:

here m=500g =>1/2 kg

u=20m/s

v=0  

t=0.02 seconds

calculation :

V=U+AT

0=20+0.02A

-20=0.02A

A=-1000 m/s^2

F=ma  

F=1/2 (-1000)

F=-500 N

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