Math, asked by abhaysahani4150, 1 year ago

A merchand bought two calculators which together cost him 4800.He sold one of them at a loss of 15% and other at a gain of 19% . If the selling price of both the calculator is equal find the cost price of the lower priced calculator.

Answers

Answered by brajmohank94
282

Let S.P. = a

C.P. of 1st calculator= a x 100/( 100 - 15 ) = a x 100/85 = 20a/17

C.P. of 2nd calculator = a x 100/( 100 + 19 ) = a x 100/119 = 100a/119

a/q

20a/17 + 100a/119 = 4800

240a/119 = 4800

a = 2380

C.P. Of 1st cal. = 20 x 2380/17 = 2800

C.P. of 2nd cal. = 4800 - 2800 = 2000

C.P. of lower priced calculator = Rs. 2000


Hope it help u

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piyysh15: thanks very much
brajmohank94: wlcm
Answered by prachikalantri
10

Let Sp=a

CP of 1 it calculator =a\times 100/(100-15)

=a\times \frac{100}{85}

=\frac{20a}{119}

CP of a 2nd calculator =a\times 100/(100+19)

=a\times \frac{100}{119}

=\frac{100a}{119}

According to question,

20a/17+100a/119=4800

240a/119=4800

a=2380

CP of 1st calculator =20\times 2380/18=2800

CP of 2nd calculator =4800-2800=2000

The CP of lower price calculator =Rs 2000

#SPJ2

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