Math, asked by jaatryaan4066, 1 year ago

A merchant buys two items for Rs. 7500. One item he sells at a profit of 16% and the other item at 14% loss. In the deal, the merchant makes neither any profit nor any loss. What is the difference between the selling price of both the items?

Answers

Answered by Anonymous
4
Hey mate ^_^

=======
Answer:
=======

Let the C.P of one item is Rs. x and that of other is Rs. (7500 - x)

According to the data given,

C.P = S.P

x \times ( \frac{116}{100} ) + (7500 - x) \times ( \frac{86}{100} )= 7500

30x = 105000 \\

x = 3500

Required difference between selling prices,

 = [( \frac{3500}{100} ) \times 116] - [( \frac{4000}{100} ) \times 86]

= 4060-3440

= Rs. 620

Therefore,

Correct option A) Rs. 620

#Be Brainly❤️
Answered by AJThe123456
7
Heyy mate ❤✌✌❤

Here's your Answer...

⤵️⤵️⤵️⤵️⤵️⤵️⤵️

Let the C.P of one item is Rs. P
and that of other is Rs. (7500 - P)

According to the data given

C.P = S.P 

=> Px(116/100) + (7500-P)x(86/100) = 7500 

=> 30P = 105000

=> P = 3500

Required difference between selling price

= Rs. [(3500/100) x 116] - [(4000/100) x 86]

= 4060-3440

= Rs. 620
✔✔✔
Similar questions