Math, asked by parmarkhushal113, 6 months ago

A merchant has three kinds of milk : 435 litres, 493 litres and 551 litres. find the least number of casks of equal size required to store all the milk without mixing explain ​

Answers

Answered by gurparshadv32
3

Answer:

As minimum number of containers are required, the size of the container should be maximum and the size is also equal. so size of the container will be HCF of 493, 551 and 435 i.e., 29 So, required number of containers is =  (493+551+435)/29= 51

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