Question

A merchant has three kinds of milk 435litre , 493 litre and551 litres Find the least number of casks of equal size required to store all the milk without mixing

Answer 1

(435+493+551)/29 = 51. because hcf of these numbers is 29. hcf is qantity of each casks for nox mixing each other

Answer 2

The total caskets will be 51.

Given:

First quantity = 435

Second quantity = 493

Third quantity = 551

To Find:

Least number of caskets required to store all the milk without mixing

Solution:

Finding the HCF of three quantities -

435 = 3 × 5 × 29

493 = 17 × 29

551 = 19 × 29

Therefore, the HCF will be 29 as it is common in all the numbers.

Now,

Number of caskets -

= 435/29 + 493/29 + 551/29

= 15 + 17 + 19

= 51

Answer: The total caskets will be 51.

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