Question

A merchant selling sunglasses can place 8 large boxes or 10 small boxes into a carton for shipping. In one shipment, he sent a total of 566 boxes of sunglasses. If there are more large boxes than small boxes, how many cartons did he ship?

Answer 1

Let large be 10x

small be 8y

acc to que

10x+8y=566

Answer 2

Answer:

Number of cartoons are 69 or 70.

Step-by-step explanation:

Given : A merchant selling sunglasses can place 8 large boxes or 10 small boxes into a carton for shipping. In one shipment, he sent a total of 566 boxes of sunglasses. If there are more large boxes than small boxes.

To find : How many cartons did he ship?

Solution :  

Let the number of large sunglasses be 'x'

Let the number of small sunglasses be 'y'

According to question,

Total number of sunglasses boxes = 566

$x+y=566$ .....(1)

A merchant selling sunglasses can place 8 large boxes or 10 small boxes into a carton for shipping.

Number of cartoons is $n=\frac{x}{8}+\frac{y}{10}$

There are more large boxes than small boxes i.e. x>y

We have to divides the 566 in such a way that all conditions will fulfilled.

Case 1 : If we assume x = 536 and y = 30

Then, $\frac{x}{8}=\frac{536}{8}=67$

$\frac{y}{10}=\frac{30}{10}=3$

So, total number of cartoons n=67+3=70

Case 2 : If we assume x = 496 and y = 70

Then, $\frac{x}{8}=\frac{496}{8}=62$

$\frac{y}{10}=\frac{70}{10}=7$

So, total number of cartoons n=62+7=69