Science, asked by shivansh012345, 9 months ago

A metal article is to be electroplated with silver. The electrolyte selected is sodium

argentocyanide.- [5]

i. What kind of salt is sodium argentocyanide?

ii. Why is it preferred to silver nitrate as an electrolyte?

iii.State one condition to ensure that the deposit is smooth ,firm and long lasting.

iv.Write the reaction taking place at the cathode.

v. Write the reaction taking place at the anode.

Answers

Answered by Anonymous
30

Explanation:

(i) Sodium argentocyanide is a complex salt. 

(ii) It is preferred over silver nitrate because it gives a smooth and firm silver plating over article. 

(iii) A low voltage current passed for a longer time.

(iv) Ag+ + e- ----> Ag

(v) Ag - e- -----> Ag+

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Answered by Itzheartcracer
2

Given :-

A metal article is to be electroplated with silver. The electrolyte selected is sodium argentocyanide

To Find :-

(i) What kind of salt is sodium argentocyanide?

(ii) Why is it preferred to silver nitrate as an electrolyte?

(iii) State one condition to ensure that the deposit is smooth, firm and long lasting. (iv) Write the reaction taking place at the cathode.

(v) Write the reaction taking place at the anode.

Solution :-

(i) What kind of salt is sodium argentocyanide

Ans - Sodium argentocyanide is an example of a complex salt.

(ii) Why is it preferred to silver nitrate as an electrolyte?

Ans - It is preferred to silver nitrate as an electrolyte because silver nitrate because it has the property of passing current through it. It is also because it deposit the smooth, firm over the material

(iii) State one condition to ensure that the deposit is smooth, firm and long lasting

Ans - The condition to ensure that the deposit is smooth, firm and long-lasting is :-

(i) Silver nitrate should be used. So, that the deposit is smooth, firm and long-lasting

(ii) Also, we may paßs the current through it  

(iv) Write the reaction taking place at the cathode.

Ag⁺ + e⁻ ⇒ Ag  

(v) Write the reaction taking place at the anode.

Ag⁺ + e⁻ ⇒ Ag⁺

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