A metal ball of mass 2 kg moving with speed 10 m/s collides head on with another stationary ball of mass 4 kg. If after collision both balls move together, then loss in kinetic energy of system due to collision will be
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Given A metal ball of mass 2 kg moving with speed 10 m/s collides head on with another stationary ball of mass 4 kg. If after collision both balls move together, then loss in kinetic energy of system due to collision will be
- So given mass of metal ball m1 = 2kg
- Speed = 10 m/s
- Mass of stationary ball m2 = 4kg
- Applying law of conservation of momentum we get
- v = m1v1 + m2v2 / m1 + m2
- = 2 x 10 + 4 x 0 / 2 + 4
- = 20 / 6
- = 3.33 m/s
- Now we have loss of energy
- = ½ m1v1^2 + ½ m2v2^2 – ½ (m1 + m2)v^2
- = ½ x 2 x (10)^2 + ½ x 4 (0)^2 – ½ (2 + 4)(3.33)^2
- = 100 – 33.2667
- = 66.7333 J
Reference link will be
https://brainly.in/question/3866920
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