Question

A metal ball of mass 200 gram at 83 degree is plunged into 300 gram of water at 30 degree. If the final temperature of the mixture is 33 degree, What is the value of specific het capacity of that metal?

Answer 1

Answer:

A metal ball of mass 200 gram at 83 degree is plunged into 300 gram of water at 30 degree. If the final temperature of the mixture is 33 degree, What is the value of specific het capacity of that metal?

Explanation:

A metal ball of mass 200 gram at 83 degree is plunged into 300 gram of water at 30 degree. If the final temperature of the mixture is 33 degree, What is the value of specific het capacity of that metal?

Answer 2

Answer:

378 J

Explanation:

Soln,

  Given,

 Case 1,

 Mass of metal = 200 g

 Temperature (metal) = 83 degree

 S.P.H = ??

 Case 2,

 Mass of metal = 300 g

 Temperature (water) = 30 degree

 S.P.H = 4200 j

 Final temp= 33

Now

Q1 = Q2

200*X*(83-33) = 300*4200*(33-30)

10000*X = 3780000

X = 378 J

∴The value of specific heat capacity of metal is 378 J.