Question

A metal ball of mass 5 kg falls from a height of 490 M how much time it will take to reach the ground​

Answer 1

Data: Mass - 5KG

Height (s) - 490M

To find - Time(t)

Solution -

s = ut + 1/2 gt^2

490 = 0(t) + 1/2 X 9.8

490 = 0 + 4.9 (t^2)

490/4.9 = t^2

100 = t^2

t = 10

Ans. The metal ball will take 10 seconds to reach the ground.

Answer 2

It will take 10 seconds to reach the ground.

Given : A metal ball of mass 5 kg falls from a height of 490 m.

To find : The time that the ball will take to reach the ground.

Solution :

We can simply solve this numerical problem by using the following process. (our goal is to calculate the time that the ball will take to reach the ground)

Here, we will be using the following formula of kinematics.

s = ut + ½ at²

Where,

• s = displacement
• u = initial velocity
• t = time
• a = acceleration

In this case,

• s = 490m
• u = 0 m/s (as starts from rest)
• t = ? (unknown)
• a = 9.8 m/s² (gravitational acceleration)

By, putting the available data, we get :

490 = (0 × t) + (½ × 9.8 × t²)

490 = 4.9 × t²

t² = 490/4.9

t² = 100

t = 10 seconds

(This will be considered as the final result.)

Hence, it will take 10 seconds to reach the ground.