Question

A metal ball that is 1.2 m in diameter expands by 2.2 mm when the temperature is increased by 95 ℃. What is the coefficient of thermal expansion for the ball?

Answer 1

Explanation:

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Answer 2

Given:

A metal ball that is 1.2 m in diameter expands by 2.2 mm when the temperature is increased by 95 ℃.

To find:

Coefficient of Linear Thermal Expansion?

Calculation:

The general expression of linear thermal expansion coefficient for a change in temperature (∆T) is:

$\alpha = \dfrac{\Delta L}{L\Delta T}$

$\implies \alpha = \dfrac{2.2 \times {10}^{ - 3} }{1.2 \times 95}$

$\implies \alpha = \dfrac{1.83 \times {10}^{ - 3} }{ 95}$

$\implies \alpha =0.019\times {10}^{ - 3}$

$\implies \alpha =1.9\times {10}^{ - 5} {/}^{ \circ} C$

So, coefficient of thermal expansion is 1.9 × 10^(-5) /°C.