Question

A metal bar of cross sectional area 1000 mm2 is 4m long. Aforce of 5000 N increase its length by 0.25 mm. Find Young's modulus of the metal​

Answer 1

Answer:

oh in which class you are

Answer 2

Answer:

here the answer

pls mark brainiest

Explanation:

Concept:

Axial deflection of varying cross-sectional bar

Case 1: If material are same

Δ = Δ1 + Δ2 + Δ3

Case 2: If material are also different then,

Calculation:

Given,

E = 200 GPa

For L1 = 1000 mm section, A1 = 10000 mm2

For L2 = 500 mm section, A2 = 5000 mm2

P = 1000 kN

Total Elongation = 

Total Elongation = 2.5 mm