a metal block of dimension 12cm×10cm×8cm and weight 40 kg wt is dropped on floor. find the pressure exerted by it if it dropped on the (a)-largest face (b)-smallest face
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Explanation:
mass=m=40kg
dimensions,suppose
length=12cm=0.12m
width=w=10cm=0.1m
height=h=8cm=0.08m
g=9.8m/sec²
(a) area of largest face=length×width
area=0.12×0.1=0.012m²
so Pressure=P=mg/area
P=40×9.8/0.012
P=32666 pa
(b) area of smallest face=width×height
area=0.1×0.08=0.008m²
so, Pressure=P=mg/area
P=40×9.8/0.008
P=49000 pa
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