A metal crystallises in a face centred cubic
structure. If the edge length of its unit cell is
'a', the closest approach between two atoms
in metallic crystal will be
(1) √2 a
(2)a/ √2
(3) 2a
(4) 2√2a
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hey! friend....
here is ur answer
In FCC, one of the face is like
,
2a^2=16r^2
⇒r^2=1/8a^2
⇒r=1/2√2a
Distance of closest approach =2r=a√2
hope it helps u
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