A metal cube of edge 12 cm is melted and formed into three smaller cubes. If the edges of the two smaller cubes are 6 cm and 8 cm, find the edge of the third smaller cube.
Answers
Answer:
The each edge of third smaller cube is 10 cm .
Step-by-step explanation:
Given as ;
A metal cube of edge 12 cm is melted and formed into three smaller cubes.
i.e The each edge of bigger cube = a = 12 cm
The each edge of first smaller cube = b = 6 cm
The each edge of second smaller cube = c = 8 cm
Let The each edge of third smaller cube = d cm
According to question
∵ volume of cube = edge³
A metal cube of edge 12 cm is melted and formed into three smaller cubes = each edge of first smaller cube + each edge of second smaller cube + each edge of third smaller cube
or, a³ = b³ + c³ + d³
Or, d³ = a³ - b³ - c³
Or, d³ = 12³ - 6³ - 8³
Or, d³ = 1728 - 216 - 512
Or, d³ = 1000
∴ d = ∛1000
i.e d = 10 cm
So, The each edge of third smaller cube = d = 10 cm
Hence, The each edge of third smaller cube is 10 cm . Answer
The edge of the third smaller cube is 10 cm
Step-by-step explanation:
- Given data
Side of large cube (a) =12 cm
Side of first smaller cube (b) =6 cm
Side of second smaller cube (c) =8 cm
Side of third smaller cube = d = unknown
- We know volume of cube
Volume of first smaller cube+Volume of second smaller cube+Volume of third smaller cube =Volume of large cube
So
So
d= 10 cm = This is side of third smaller cube