Ravish wanted to make a temporary shelter for his car by making a box-like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5 m with base dimensions 4 m × 3 m?
Answers
Given: Dimensions of the shelter :
L = 4 m , b = 3 m , h = 2.5 m
Required area of Tarpaulin to make the shelter = Area of four sides + area of the top of the car
Tarpaulin required to make the shelter = 2(l + b)× h + lb
= [2(4 + 3) × 2.5 + 4 × 3]
= (35 + 12)
= 47m²
Hence, 47 m² tarpaulin would be required to make the shelter.
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Given:
- L = 4 m
- b = 3 m
- h = 2.5 m
Required area of Tarpaulin to make the shelter = Area of four sides + area of the top of the car
Tarpaulin needed to make the shelter = 2(l + b)× h + lb
putting the value
= [2(4 + 3) × 2.5 + 4 × 3]
= (35 + 12)
= 47m²
Hence, 47 m² tarpaulin would be needed to make the shelter.