Question

A metal cube of edge 12 cm is melted and formed into three smaller cubes. if the edges of two smaller cubes are 6 cm and 8 cm, then find the edge of the third smaller cube. (a) 10 cm (b) 14 cm (c) 12 cm (d) 16 cm (e) 8 cm

Answer 1

the volume of metal cube = 12³cm³
we know that
volume of 3smaller cubes = volume of metal cube
6³+8³+x³=12³
728+x = 1728
x=1728-728
x=1000
x=10
so edge of small cube is 10

Answer 2

HEY DEAR ... ✌

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Given :

Edge of a bigger cube (R)= 12 m

Edge of a first smaller cube(r²)= 8 m

Edge of a second smaller cube(r2)= 6m

Volume of a cube = side³

Volume of a bigger cube(V) = (sides)³
= (12)³= 1728m³

It is melted into three other cubes ,so the volume of the smaller cubes remains same as the volume of bigger cube .



volume of the first smaller cubes(V1)= (8)³=512m³

volume of second smaller cube(V2) = 6³ = 216m³


Total volume(V) = volume of first smaller cube(V1) + volume of second smaller cube(V2)+ + volume of third smaller cube(V3)

V= V1+V2+V3

1728 = 512 +216+V3

1728 = 728+V3

1728 - 728 = V3

1000 = V3


volume of third cube = 1000 m³

Edge³= 1000

Edge = ³√1000

Edge =³√10×10×10

Edge= 10 m

Hence, the edge of the third cube is = 10m


HOPE , IT HELPS ... ✌