A metal cube of side 5 cm and density 7.9 g cm^-3 is suspended by thread and is immersed completely in a liquid of density 1.1 g cm^-3. Find: (s) the weight of cube (b) the Upthrust on cube and (c) the tension in thread.
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Given :
- side of cube = 5 cm
- density of cube = 7.9 g cm^-3
- density of liquid = 1.1 g cm^-3
To find :
- (a) the weight of cube.
- (b) the Upthrust on cube.
- (c) the tension in thread.
Solution :
(a) side of cude = 5 cm
Therefore, volume of the cube = 5 × 5 × 5 = 125 cm³
Mass of the cube = Volume × Density
= 125 cm³ x 7.9 g cm^-3
= 987.5 g
Therefore, the weight of the cude = 987.5 gf (downwards)
(b) Upthrust on cube = Weight of liquid displaced
= Volume of cube × density of liquid × g
= 125 × 1.1 × g
= 137.5 gf (upwards)
(c) Tention in thread = Net downward force
= Weight of cube - Upthrust on cube
= 987.5 - 137.5
= 850.0 gf.
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